4y^{''}+4sqrt(3)y^'+3y=0

Lösung

4 y^{^{''}} + 43 y^{^{'}} + 3 y = 0

y = c_{1} e^{- \frac{3 t}{2}} + c_{2} e^{- \frac{3 t}{2}} t

Schritte zur Lösung

4 y^{''} (t) + 43 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = c_{1} e^{- \frac{3 t}{2}} + c_{2} e^{- \frac{3 t}{2}} t

y = c_{1} e^{- \frac{3 t}{2}} + c_{2} e^{- \frac{3 t}{2}} t

(y^{^{'''}}) - 4 y^{^{''}} - 5 y^{^{'}} = 0

2 y^{^{''}} - y^{^{'}} - 3 y = 0, y (0) = 2, y^{^{'}} (0) = - \frac{7}{2}

81 y^{^{''}} + 108 y^{^{'}} - 13 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} - 3 y^{^{'}} - 4 y = 0, y (0) = 1, y (0) = 2

y^{^{''}} + 4 y^{^{'}} - 1 y = 0