y^{''}+6y^'+9y=0,y(0)=0

Lösung

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = 0

y = c_{2} e^{- 3 t} t

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 9 y = 0

Solve linear ODE:

y = c_{2} e^{- 3 t} t

y = c_{2} e^{- 3 t} t

y^{^{''}} - 6 y + 9 y = 0, y^{1} (0) = e^{3 x}

y^{^{''}} - 3 y^{^{'}} + 2 y = 0, y (0) = 1, y^{^{'}} (0) = 1

y^{^{''}} + 2 y^{^{'}} + y = 0, y (1) = 6, y^{^{'}} (0) = 6

y^{^{'''}} - 13 y^{^{''}} + 12 y^{^{'}} = 0

y^{^{''}} - 5 y + 6 y = 0, y (0) = - \frac{3}{5}, y^{^{'}} (0) = - \frac{13}{5}