2y^{''}+6y^'=0

Lösung

2 y^{^{''}} + 6 y^{^{'}} = 0

y = c_{1} + c_{2} e^{- 3 t}

Schritte zur Lösung

2 y^{''} (t) + 6 y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- 3 t}

y = c_{1} + c_{2} e^{- 3 t}

\frac{d ^{2} y}{d x ^{2}} + k \frac{d y}{d x} - k^{2} y = 0

y^{^{''}} + 2 y^{^{'}} + y = 0, y (0) = 10, y^{^{'}} (0) = - 9

y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = 1, y^{^{'}} (0) = 5

y^{^{''}} - 4 y^{^{'}} - 4 y = 0, y (0) = 2, y^{^{'}} (0) = 16

y^{^{''}} + 2 y^{^{'}} - 8 y = 0, y (0) = 3, y (0) = - 12