35y^{''''}+52y^{''}+9y=0

Lösung

35 y^{^{''''}} + 52 y^{^{''}} + 9 y = 0

y = c_{1} cos (\frac{t}{5}) + c_{2} sin (\frac{t}{5}) + c_{3} cos (\frac{3 t}{7}) + c_{4} sin (\frac{3 t}{7})

Schritte zur Lösung

35 y^{(4)} (t) + 52 y^{''} (t) + 9 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{t}{5}) + c_{2} sin (\frac{t}{5}) + c_{3} cos (\frac{3 t}{7}) + c_{4} sin (\frac{3 t}{7})

y = c_{1} cos (\frac{t}{5}) + c_{2} sin (\frac{t}{5}) + c_{3} cos (\frac{3 t}{7}) + c_{4} sin (\frac{3 t}{7})

\frac{d ^{4} y}{d t ^{4}} - y^{^{'''}} - y^{^{''}} + y^{^{'}} = 0

2 u^{^{''}} + u^{^{'}} + 3 H (t) = 0

y^{^{''}} + 2 y^{^{'}} - 10 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

2 y^{^{''}} - 0 y^{^{'}} + 18 y = 0

24 y^{^{''}} + 14 y^{^{'}} - 3 y = 0