17/160 x^{''}+0.4x^'+2x=0

Lösung

\frac{17}{160} x^{^{''}} + 0.4 x^{^{'}} + 2 x = 0

x = e^{- 1.88235 \dots t} (c_{1} cos (3.90899 \dots t) + c_{2} sin (3.90899 \dots t))

Schritte zur Lösung

\frac{17}{160} x^{''} (t) + 0.4 x^{'} (t) + 2 x = 0

Solve linear ODE:

x = e^{- 1.88235 \dots t} (c_{1} cos (3.90899 \dots t) + c_{2} sin (3.90899 \dots t))

x = e^{- 1.88235 \dots t} (c_{1} cos (3.90899 \dots t) + c_{2} sin (3.90899 \dots t))

y^{^{'''}} + 9 y^{^{'}} = 0, y (0) = - 21

y^{^{'}} + 18 y^{^{''}} + 81 y = 0

y^{^{''}} - 6 y^{^{'}} + 9 y = 0, y (0) = 1, y^{^{'}} (0) = 7

x^{^{''}} + 2 x^{^{'}} + 1000 x = 0, x (0) = 0.75, x^{^{'}} (0) = 0

y^{^{''}} + y^{^{'}} + 4 y = 0, y (0) = 3, y^{^{'}} (0) = 0