9y^{''}-18y^'+34y=0

解答

9 y^{^{''}} - 18 y^{^{'}} + 34 y = 0

y = e^{t} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

求解步骤

9 y^{''} (t) - 18 y^{'} (t) + 34 y = 0

求解线性方程:

y = e^{t} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

y = e^{t} (c_{1} cos (\frac{5 t}{3}) + c_{2} sin (\frac{5 t}{3}))

y^{^{''}} + \frac{49}{3} y = 0, y (0) = \frac{π}{8}, y^{^{'}} (0) = 0

y^{^{''}} - 2 y^{^{'}} + 10 y = 0, y (0) = 0, y^{^{'}} (0) = - 4

y^{^{''''}} + 2 y^{^{'''}} + y^{^{''}} + 8 y^{^{'}} - 12 y = 0

y^{^{''}} + 4 y^{^{'}} + 20 y = 0, y (π) = 7, y (0) = 8

y \cdot u^{2} - y^{^{''}} = 0