150y^{'''}+25y^{''}+y^'=0

Lösung

150 y^{^{'''}} + 25 y^{^{''}} + y^{^{'}} = 0

y = c_{1} + c_{2} e^{- \frac{t}{15}} + c_{3} e^{- \frac{t}{10}}

Schritte zur Lösung

150 y^{'''} (t) + 25 y^{''} (t) + y^{'} (t) = 0

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{t}{15}} + c_{3} e^{- \frac{t}{10}}

y = c_{1} + c_{2} e^{- \frac{t}{15}} + c_{3} e^{- \frac{t}{10}}

y^{^{''}} + \frac{y}{4} = 0, y (0) = 0

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = - 5, y^{^{'}} (0) = 14

y^{^{''}} = y, y (0) = 0, y^{^{'}} (1) = 1

\frac{d ^{2} y}{d t ^{2}} - 11 \frac{d y}{d t} + 10 y = 0

y^{^{''}} - y^{^{'}} - 30 y = 0, y (0) = - 2, y^{^{'}} (0) = 21