y^{''}+6y^'+34y=0,y(0)=2,y^'(0)=-4

Lösung

y^{^{''}} + 6 y^{^{'}} + 34 y = 0, y (0) = 2, y^{^{'}} (0) = - 4

y = e^{- 3 t} (2 cos (5 t) + \frac{2}{5} sin (5 t))

Schritte zur Lösung

y^{''} (t) + 6 y^{'} (t) + 34 y = 0

Solve linear ODE:

y = e^{- 3 t} (2 cos (5 t) + \frac{2}{5} sin (5 t))

y = e^{- 3 t} (2 cos (5 t) + \frac{2}{5} sin (5 t))

4 y^{^{''}} - 4 y^{^{'}} - 3 y = 0, y (0) = 1, y^{^{'}} (1) = 1

y^{^{''}} + 6 y^{^{'}} + 9 y = 0, y (0) = e^{- 3 x}

2 y^{^{''}} - 7 y^{^{'}} + 5 y = 0, y (0) = 4, y^{^{'}} (0) = 5.5

y^{^{''}} - 6 y^{^{'}} - 7 y = 0, y (0) = 5, y^{^{'}} (0) = - 5

\frac{d ^{2} y}{d t ^{2}} + 18 \frac{d y}{d t} + 81 y = 0