10x^{''}+40x^'+1/50 x=0

Lösung

10 x^{^{''}} + 40 x^{^{'}} + \frac{1}{50} x = 0

x = c_{1} e^{\frac{( - 100 + 9995 ) t}{50}} + c_{2} e^{- \frac{( 100 + 9995 ) t}{50}}

Schritte zur Lösung

10 x^{''} (t) + 40 x^{'} (t) + \frac{1}{50} x = 0

Solve linear ODE:

x = c_{1} e^{\frac{( - 100 + 9995 ) t}{50}} + c_{2} e^{- \frac{( 100 + 9995 ) t}{50}}

x = c_{1} e^{\frac{( - 100 + 9995 ) t}{50}} + c_{2} e^{- \frac{( 100 + 9995 ) t}{50}}

y^{^{''}} + 2 y^{^{'}} + 26 y = 0, y (0) = 3, y^{^{'}} (0) = - 1

y^{^{''}} - 12 y^{^{'}} + 52 y = 0, y (\frac{π}{8}) = 1, y (0) = 8

y^{^{''}} + y = 0, y^{^{'}} (π) = 1, y (0) = 1

y^{^{'''}} - 2 y^{^{''}} - 29 y^{^{'}} - 42 y = 0

\frac{1}{2} x^{^{''}} + \frac{3}{2} x^{^{'}} + x = 0