y^{''}-22y^'+112y=0

Lösung

y^{^{''}} - 22 y^{^{'}} + 112 y = 0

y = c_{1} e^{14 t} + c_{2} e^{8 t}

Schritte zur Lösung

y^{''} (t) - 22 y^{'} (t) + 112 y = 0

Solve linear ODE:

y = c_{1} e^{14 t} + c_{2} e^{8 t}

y = c_{1} e^{14 t} + c_{2} e^{8 t}

y^{^{''}} + 12 y^{^{'}} + 12 y = 0

0.5 y^{^{''}} + 0.5 y^{^{'}} + y = 0

y^{^{''}} - 10 y^{^{'}} - 144 y = 0, y (0) = 11, y^{^{'}} (0) = 94

y^{^{''}} - 6 y^{^{'}} + 13 y = 0, y (\frac{π}{4}) = 1, y (0) = 9

y^{^{''''}} + 3 y^{^{'''}} + 2 y^{^{''}} + 6 y^{^{'}} = 0