y^{''}+0y^'+16y=0

Lösung

y^{^{''}} + 0 y^{^{'}} + 16 y = 0

y = c_{1} cos (4 t) + c_{2} sin (4 t)

Schritte zur Lösung

y^{''} (t) + 0 y^{'} (t) + 16 y = 0

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t)

y^{^{''}} + 4 y^{^{'}} + 29 y = 0, y (0) = 3, y^{^{'}} (0) = - 5

y^{^{'''}} - 2 y^{^{''}} - 63 y^{^{'}} = 0

\frac{3}{4} x^{^{''}} + 72 x = 0, x (0) = - \frac{1}{4}, x^{^{'}} (0) = 0

\frac{1}{16} x^{^{''}} + x^{^{'}} + 4 x = 0

y^{^{''}} - 4 y^{^{'}} - 5 y = 0, y (1) = 0, y (1) = 2