f^{''}(x)=3x+1

Lösung

f^{^{''}} (x) = 3 x + 1

f (x) = \frac{x ^{3}}{2} + \frac{x ^{2}}{2} + c_{1} x + c_{2}

Schritte zur Lösung

f^{''} (x) = 3 x + 1

Löse

f^{''} (x) = 3 x + 1 : f^{'} (x) = \frac{3 x ^{2}}{2} + x + c_{1}

Löse

f^{'} (x) = \frac{3 x ^{2}}{2} + x + c_{1} : f (x) = \frac{x ^{3}}{2} + \frac{x ^{2}}{2} + c_{1} x + c_{2}

f (x) = \frac{x ^{3}}{2} + \frac{x ^{2}}{2} + c_{1} x + c_{2}

2 y^{^{'''}} = e^{x} y^{^{'''}}

f^{^{'}} (x) = 4 x + 9

2 y^{^{'}} + y^{3} = 0

2 x^{2} y^{^{'}} = x^{2} + y^{2}

x^{3} y^{^{'''}} - x^{2} y^{^{'}} = 0