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tangent y=sqrt(x),(36,6)

解答

切线

y = x, (36, 6)

解答

y = \frac{1}{12} x + 3

求解步骤

计算

y = x

的斜率:

\frac{d y}{d x} = \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{12}

找到斜率 m=

\frac{1}{12}

且穿过

(36, 6)

的直线:

y = \frac{1}{12} x + 3

y = \frac{1}{12} x + 3

作图

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