y^{''}+2y^'+5y=10

Lösung

y^{^{''}} + 2 y^{^{'}} + 5 y = 10

y = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t)) + 2

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 5 y = 10

Solve linear ODE:

y = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t)) + 2

y = e^{- t} (c_{1} cos (2 t) + c_{2} sin (2 t)) + 2

x \to 4 lim (\frac{x ^{2} - 9}{x - 3})

a re a \frac{sec ^{2} ( x )}{2}, 2 cos^{2} (x)

x \to 0 lim (\frac{1}{5 + 5})

\frac{d y}{d x} + 2 y = 1

\frac{d y}{d x} + 3 x^{2} \cdot y = 6 x^{2}