y^'=-0.5y^{1.5}

Lösung

y^{^{'}} = - 0.5 y^{1.5}

y = \frac{4}{0.25 t ^{2} - c _{1} t + c _{1}^{2}}

Schritte zur Lösung

y^{'} (t) = - 0.5 y^{1.5}

Solve separable ODE:

y = \frac{4}{0.25 t ^{2} - c _{1} t + c _{1}^{2}}

y = \frac{4}{0.25 t ^{2} - c _{1} t + c _{1}^{2}}

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