What is (\partial)/(\partial y)(y/((x+y)^2)) ?

The answer to (\partial)/(\partial y)(y/((x+y)^2)) is (-y+x)/((x+y)^3)

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(\partial)/(\partial y)(y/((x+y)^2))

\frac{\partial}{\partial y} (\frac{y}{( x + y ) ^{2}})

\frac{- y + x}{( x + y ) ^{3}}

Solution steps

\frac{\partial}{\partial y} (\frac{y}{( x + y ) ^{2}})

Treat

x

as a constant

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{\partial}{\partial y} ( y ) ( x + y ) ^{2} - \frac{\partial}{\partial y} ( ( x + y ) ^{2} ) y}{( ( x + y ) ^{2} ) ^{2}}

\frac{\partial}{\partial y} (y) = 1

\frac{\partial}{\partial y} ((x + y)^{2}) = 2 (x + y)

= \frac{1 \cdot ( x + y ) ^{2} - 2 ( x + y ) y}{( ( x + y ) ^{2} ) ^{2}}

Simplify

\frac{1 \cdot ( x + y ) ^{2} - 2 ( x + y ) y}{( ( x + y ) ^{2} ) ^{2}} : \frac{- y + x}{( x + y ) ^{3}}

= \frac{- y + x}{( x + y ) ^{3}}

\frac{\partial}{\partial x} (e^{- 2 t} cos (π x))

\frac{d y}{d t} = \frac{t}{y e ^{y + t^{2}}}

\int \frac{x ^{2}}{a ^{2} + ( x - b ) ^{2}} d x

\int 5 x cos (8 x) d x

d er i v a t i v e f (x) = x^{3} (x - 4)^{2}

What is (\partial)/(\partial y)(y/((x+y)^2)) ?
The answer to (\partial)/(\partial y)(y/((x+y)^2)) is (-y+x)/((x+y)^3)