(x^2+2xy)dx+xdy=0

Lösung

(x^{2} + 2 x y) d x + x d y = 0

y = - \frac{2 x - 1}{4} + \frac{c _{1}}{e ^{2 x}}

Schritte zur Lösung

(x^{2} + 2 x y) d x + x d y = 0

Solve linear ODE:

y = - \frac{2 x - 1}{4} + \frac{c _{1}}{e ^{2 x}}

y = - \frac{2 x - 1}{4} + \frac{c _{1}}{e ^{2 x}}

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