(\partial)/(\partial y)(ln(3xy)+x^2)

Lösung

\frac{\partial}{\partial y} (ln (3 x y) + x^{2})

\frac{1}{y}

Schritte zur Lösung

\frac{\partial}{\partial y} (ln (3 x y) + x^{2})

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (ln (3 x y)) + \frac{\partial}{\partial y} (x^{2})

\frac{\partial}{\partial y} (ln (3 x y)) = \frac{1}{y}

\frac{\partial}{\partial y} (x^{2}) = 0

= \frac{1}{y} + 0

Vereinfache

= \frac{1}{y}

\frac{\partial}{\partial y} (\frac{y}{( 2 x + 3 y )})

x \to \infty lim (- 1)

a re a 2 x^{2}, x^{4} - 2 x^{2}

\frac{\partial}{\partial y} (1 + 3 x + 2 y^{2})

\frac{d}{d x} (\frac{x + 1}{x ^{2} + 1})