3(y^4+1)dx+(4xy^3)dy=0

Lösung

3 (y^{4} + 1) d x + (4 x y^{3}) d y = 0

y = 4 \frac{c _{1} - x ^{3}}{x ^{3}}, y = - 4 \frac{c _{1} - x ^{3}}{x ^{3}}

Schritte zur Lösung

3 (y^{4} + 1) d x + (4 x y^{3}) d y = 0

Solve separable ODE:

y = 4 \frac{c _{1} - x ^{3}}{x ^{3}}, y = - 4 \frac{c _{1} - x ^{3}}{x ^{3}}

y = 4 \frac{c _{1} - x ^{3}}{x ^{3}}, y = - 4 \frac{c _{1} - x ^{3}}{x ^{3}}

\int \frac{1}{( y - 1 )} d y

x \to 4 lim (20 - x^{2})

\frac{\partial}{\partial y} (x^{2} + y^{2} + z^{2} - 1)

\frac{d y}{d x} = cos (x) (1 + 3 y)

\int_{2}^{4} \frac{x}{6} (2 x - 3) d x