What is the derivative of 1/4 e^x+e^{-x} ?

The derivative of 1/4 e^x+e^{-x} is 1/4 e^x-e^{-x}

What is the first derivative of 1/4 e^x+e^{-x} ?

The first derivative of 1/4 e^x+e^{-x} is 1/4 e^x-e^{-x}

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\frac{d}{d x} (\frac{1}{4} e^{x} + e^{- x})

\frac{1}{4} e^{x} - e^{- x}

Solution steps

\frac{d}{d x} (\frac{1}{4} e^{x} + e^{- x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{4} e^{x}) + \frac{d}{d x} (e^{- x})

\frac{d}{d x} (\frac{1}{4} e^{x}) = \frac{1}{4} e^{x}

\frac{d}{d x} (e^{- x}) = - e^{- x}

= \frac{1}{4} e^{x} - e^{- x}

\frac{d}{d x} (\frac{d y}{d x}) + 4 y = 0

\int \frac{sin ^{2} ( x )}{x} d x

\int \frac{1}{2 x ^{3} + 2 x ^{2}} d x

\frac{d}{d x} (arcsin (3 x^{2}))

- 2 y

What is the derivative of 1/4 e^x+e^{-x} ?
The derivative of 1/4 e^x+e^{-x} is 1/4 e^x-e^{-x}
What is the first derivative of 1/4 e^x+e^{-x} ?
The first derivative of 1/4 e^x+e^{-x} is 1/4 e^x-e^{-x}