What is the integral from 1 to 1.5 of (1/8+3/8 x) ?

The integral from 1 to 1.5 of (1/8+3/8 x) is 0.296875

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integral from 1 to 1.5 of (1/8+3/8 x)

\int_{1}^{1.5} (\frac{1}{8} + \frac{3}{8} x) d x

0.296875

Solution steps

\int_{1}^{1.5} \frac{1}{8} + \frac{3}{8} x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{1.5} \frac{1}{8} d x + \int_{1}^{1.5} \frac{3}{8} x d x

\int_{1}^{1.5} \frac{1}{8} d x = 0.0625

\int_{1}^{1.5} \frac{3}{8} x d x = 0.234375

= 0.0625 + 0.234375

Simplify

= 0.296875

x \to - \infty lim (x^{1})

\int_{0}^{π} 11 sin^{2} (2 x) d x

d er i v a t i v e y = ln (8 x^{2} - 7 x + 9)

d er i v a t i v e f (t) = e^{9 t s i n (2 t)}

d er i v a t i v e \frac{x ^{2}}{x + 8}

What is the integral from 1 to 1.5 of (1/8+3/8 x) ?
The integral from 1 to 1.5 of (1/8+3/8 x) is 0.296875