What is the derivative of 2cos(2x-2sin(2x)) ?

The derivative of 2cos(2x-2sin(2x)) is -4sin(2x)-4cos(2x)

What is the first derivative of 2cos(2x-2sin(2x)) ?

The first derivative of 2cos(2x-2sin(2x)) is -4sin(2x)-4cos(2x)

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\frac{d}{d x} (2 cos (2 x) - 2 sin (2 x))

- 4 sin (2 x) - 4 cos (2 x)

Solution steps

\frac{d}{d x} (2 cos (2 x) - 2 sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (2 x)) - \frac{d}{d x} (2 sin (2 x))

\frac{d}{d x} (2 cos (2 x)) = - 4 sin (2 x)

\frac{d}{d x} (2 sin (2 x)) = 4 cos (2 x)

= - 4 sin (2 x) - 4 cos (2 x)

\frac{d}{d x} (ln 1 + x - x^{3})

\int \frac{1}{x 1 + x ^{n}} d x

x \to \infty lim ((a)^{x})

y^{^{'}} + 3 x^{2} y = sin (x) e^{- x^{3}}, y (0) = 1

d er i v a t i v e x^{3} b^{5} + y^{4} b + z^{6}

What is the derivative of 2cos(2x-2sin(2x)) ?
The derivative of 2cos(2x-2sin(2x)) is -4sin(2x)-4cos(2x)
What is the first derivative of 2cos(2x-2sin(2x)) ?
The first derivative of 2cos(2x-2sin(2x)) is -4sin(2x)-4cos(2x)