What is area x^3,x^{1/3},[0,2] ?

The answer to area x^3,x^{1/3},[0,2] is 5-3/(2^{2/3)}

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area x^3,x^{1/3},[0,2]

area

x^{3}, x^{\frac{1}{3}}, [0, 2]

5 - \frac{3}{2 ^{\frac{2}{3}}}

Decimal

3.11011 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} x^{3} - x^{\frac{1}{3}} d x

Solve

\int_{0}^{2} x^{3} - x^{\frac{1}{3}} d x : 5 - \frac{3}{2 ^{\frac{2}{3}}}

The area is:

= 5 - \frac{3}{2 ^{\frac{2}{3}}}

\frac{d}{d x} (\frac{x - 1}{x + 3})

\int sin (2 π x) d x

\int_{0}^{1} e^{t} d t

\int p (p + 8)^{5} d p

\int e^{(2 x)} d x

What is area x^3,x^{1/3},[0,2] ?
The answer to area x^3,x^{1/3},[0,2] is 5-3/(2^{2/3)}