y^{''}+2y^'+2y=sin(5t)

Lösung

y^{^{''}} + 2 y^{^{'}} + 2 y = sin (5 t)

y = e^{- t} (c_{1} cos (t) + c_{2} sin (t)) - \frac{23}{629} sin (5 t) - \frac{10}{629} cos (5 t)

Schritte zur Lösung

y^{''} (t) + 2 y^{'} (t) + 2 y = sin (5 t)

Solve linear ODE:

y = e^{- t} (c_{1} cos (t) + c_{2} sin (t)) - \frac{23}{629} sin (5 t) - \frac{10}{629} cos (5 t)

y = e^{- t} (c_{1} cos (t) + c_{2} sin (t)) - \frac{23}{629} sin (5 t) - \frac{10}{629} cos (5 t)

x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}, y (1) = \frac{1}{2}

\int ln (8 x) d x

d er i v a t i v e sin (5 x - 3)

\int 9 x^{2} 4 7 + 4 x^{3} d x

\frac{\partial}{\partial x} (y sin (\frac{y}{x}))