xy^'+3y=4x,y(3)=6

Lösung

x y^{^{'}} + 3 y = 4 x, y (3) = 6

y = x + \frac{81}{x ^{3}}

Schritte zur Lösung

x y^{'} (x) + 3 y = 4 x

Solve linear ODE:

y = x + \frac{81}{x ^{3}}

y = x + \frac{81}{x ^{3}}

\frac{\partial}{\partial x} (x^{3} - 6 x y + y^{3})

\frac{\partial}{\partial z} (z^{3} - x^{2} y)

y^{^{'}} = \frac{2 t}{y + t ^{2} y}

n \to \infty lim (\frac{1}{n !})

x \to 0 lim (\frac{1}{x ^{2} ( x + 8 )})