What is the tangent of f(x)=e^{x^7},(-1, 1/e) ?

The tangent of f(x)=e^{x^7},(-1, 1/e) is y= 7/e x+8/e

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tangent of f(x)=e^{x^7},(-1, 1/e)

tangent of

f (x) = e^{x^{7}}, (- 1, \frac{1}{e})

y = \frac{7}{e} x + \frac{8}{e}

Solution steps

Find the slope of

f (x) = e^{x^{7}} : \frac{df ( x )}{d x} = e^{x^{7}} \cdot 7 x^{6}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{7}{e}

Find the line with slope m=

\frac{7}{e}

and passing through

(- 1, \frac{1}{e}) : y = \frac{7}{e} x + \frac{8}{e}

y = \frac{7}{e} x + \frac{8}{e}

d er i v a t i v e y = x^{3} - 3 x

\frac{d}{d x} (\frac{1 + sin ( x )}{1 + cos ( x )})

d er i v a t i v e (2 r a^{r x} + n)^{p}

\frac{d}{d x} (x - 0.8 - 0.2 sin (x))

8 cos^{2} (y) d x + csc^{2} (x) d y = 0, y (\frac{π}{12}) = \frac{π}{4}

What is the tangent of f(x)=e^{x^7},(-1, 1/e) ?
The tangent of f(x)=e^{x^7},(-1, 1/e) is y= 7/e x+8/e