(\partial)/(\partial y)(3x^2-2xy+2)

Lösung

\frac{\partial}{\partial y} (3 x^{2} - 2 x y + 2)

- 2 x

Schritte zur Lösung

\frac{\partial}{\partial y} (3 x^{2} - 2 x y + 2)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) - \frac{\partial}{\partial y} (2 x y) + \frac{\partial}{\partial y} (2)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

\frac{\partial}{\partial y} (2) = 0

= 0 - 2 x + 0

Vereinfache

= - 2 x

\frac{\partial}{\partial x} (ln (\frac{3 x y}{5 z}))

\int (2 x + 1) x - 5 d x

a re a ∣ 4 x - 1 ∣, x^{2} - 5

\frac{d y}{d x} = - (\frac{y ^{2}}{1 + y ^{2}} e^{(- x)})

x \to 0 lim (\frac{1}{8} + x - (\frac{1}{8}))