(dy)/(dt)=((4y^2-t^2))/(2ty)

Lösung

\frac{d y}{d t} = \frac{( 4 y ^{2} - t ^{2} )}{2 t y}

y = \frac{t 2 c _{1} t ^{2} + 1}{2}, y = - \frac{t 2 c _{1} t ^{2} + 1}{2}

Schritte zur Lösung

\frac{d y}{d t} = \frac{( 4 y ^{2} - t ^{2} )}{2 t y}

Solve Bernoulli ODE:

y = \frac{t 2 c _{1} t ^{2} + 1}{2}, y = - \frac{t 2 c _{1} t ^{2} + 1}{2}

y = \frac{t 2 c _{1} t ^{2} + 1}{2}, y = - \frac{t 2 c _{1} t ^{2} + 1}{2}

\int (\frac{1}{2 x ^{3}} + \frac{1}{x ^{2}}) d x

x \to 0 lim (5 + \frac{9}{x ^{3}})

\frac{x d y}{d x} + y = 6 x + 1

\int \frac{csc ^{2} ( x )}{cot ^{7} ( x )} d x

d er i v a t i v e f (x) = \frac{ln ( x )}{20 + x}