integral from 0 to sqrt(3 of)(6/(1+x^2))

Lösung

\int_{0}^{3} (\frac{6}{1 + x ^{2}}) d x

2 π

Dezimale

6.28318 \dots

Schritte zur Lösung

\int_{0}^{3} \frac{6}{1 + x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{3} \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 6 [arctan (x)]_{0}^{3}

Berechne die Grenzen:

\frac{π}{3}

= 6 \cdot \frac{π}{3}

Vereinfache

= 2 π

x \to 0 lim ((3 x - 4)^{4})

d er i v a t i v e 2 e^{\frac{s i n ( w )}{3}} + 1

\frac{d}{d x} (x^{2} 4 x - 3)

x \to 4 - lim (x^{2} + 2)

x \to 0 - lim (\frac{2}{9 x ^{\frac{1}{3}}})