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tangent f(x)=(6x+5)/(x-1),\at x=2

解答

切线

f (x) = \frac{6 x + 5}{x - 1}, at x = 2

解答

y = - 11 x + 39

求解步骤

找到切点:

(2, 17)

计算

f (x) = \frac{6 x + 5}{x - 1}

的斜率:

\frac{df ( x )}{d x} = - \frac{11}{( x - 1 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 11

找到斜率 m=

- 11

且穿过

(2, 17)

的直线:

y = - 11 x + 39

y = - 11 x + 39

作图

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