What is the limit as x approaches 1 of ln(5x)+e^x ?

The limit as x approaches 1 of ln(5x)+e^x is ln(5)+e

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limit as x approaches 1 of ln(5x)+e^x

x \to 1 lim (ln (5 x) + e^{x})

ln (5) + e

Decimal

4.32771 \dots

Solution steps

x \to 1 lim (ln (5 x) + e^{x})

Plug in the value

x = 1

= ln (5 \cdot 1) + e^{1}

Simplify

= ln (5) + e

\frac{d y}{d x} = (x - 3) e^{- 2 y}

\int ln (t + 1) d t

\frac{d}{d x} (\frac{sin ( x )}{x ^{5}})

\frac{d}{d x} (x^{4} - 2 x^{2} + 3)

t an g e n t y = (x^{3} - 9 x)^{10}, (3, 0)

What is the limit as x approaches 1 of ln(5x)+e^x ?
The limit as x approaches 1 of ln(5x)+e^x is ln(5)+e