y^'-t^2y=0

Lösung

y^{^{'}} - t^{2} y = 0

y = e^{\frac{t ^{3}}{3} + c_{1}}

Schritte zur Lösung

y^{'} (t) - t^{2} y = 0

Solve separable ODE:

y = e^{\frac{t ^{3}}{3} + c_{1}}

y = e^{\frac{t ^{3}}{3} + c_{1}}

x \to 0 lim (\frac{1}{x} - \frac{1}{e ^{x}})

in v erse l a pl a ce \frac{1}{( s ^{2} + 1 ) ( s ^{2} + 16 )}

x \to 2 lim (x^{2} - 4 x + 5)

\frac{\partial}{\partial x} (3 x + x y + x^{2} y - 2 y)

\frac{\partial}{\partial x} (\frac{1}{∣ x ∣})