y^{''}+5y^'=e^{-t},y(0)=0,y^'(0)=0

Lösung

y^{^{''}} + 5 y^{^{'}} = e^{- t}, y (0) = 0, y^{^{'}} (0) = 0

y = - \frac{1}{20} + \frac{1}{4} + \frac{1}{20} e^{- 5 t} - \frac{1}{4} e^{- t}

Schritte zur Lösung

y^{''} (t) + 5 y^{'} (t) = e^{- t}

Solve linear ODE:

y = - \frac{1}{20} + \frac{1}{4} + \frac{1}{20} e^{- 5 t} - \frac{1}{4} e^{- t}

y = - \frac{1}{20} + \frac{1}{4} + \frac{1}{20} e^{- 5 t} - \frac{1}{4} e^{- t}

\frac{\partial}{\partial z} (e^{x} + yz)

s im pl i f y f (x)

x \to 6 + lim (\frac{x}{36 - x ^{2}})

\frac{d}{d x} (2 x arcsin (x))

x \to 2 lim ([x])