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人気のある微分積分 >

integral of sin^4(1/2 x)cos^4(1/2 x)

解

\int sin^{4} (\frac{1}{2} x) cos^{4} (\frac{1}{2} x) d x

解

2 (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{16} (x - sin (x)) - \frac{3}{256} (5 (3 (x - sin (x)) - 4 sin^{3} (\frac{x}{2}) cos (\frac{x}{2})) - 16 sin^{5} (\frac{x}{2}) cos (\frac{x}{2})) - \frac{1}{8} sin^{7} (\frac{x}{2}) cos (\frac{x}{2})) + C

解答ステップ

\int sin^{4} (\frac{1}{2} x) cos^{4} (\frac{1}{2} x) d x

簡素化

sin^{4} (\frac{1}{2} x) cos^{4} (\frac{1}{2} x) : sin^{4} (\frac{x}{2}) cos^{4} (\frac{x}{2})

= \int sin^{4} (\frac{x}{2}) cos^{4} (\frac{x}{2}) d x

u置換積分法を適用する

= \int sin^{4} (u) cos^{4} (u) \cdot 2 d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin^{4} (u) cos^{4} (u) d u

三角関数の公式を使用して書き換える

= 2 \cdot \int sin^{4} (u) (1 - sin^{2} (u))^{2} d u

拡張

sin^{4} (u) (1 - sin^{2} (u))^{2} : sin^{4} (u) - 2 sin^{6} (u) + sin^{8} (u)

= 2 \cdot \int sin^{4} (u) - 2 sin^{6} (u) + sin^{8} (u) d u

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int sin^{4} (u) d u - \int 2 sin^{6} (u) d u + \int sin^{8} (u) d u)

\int sin^{4} (u) d u = - \frac{1}{4} sin^{3} (u) cos (u) + \frac{3}{8} (u - \frac{1}{2} sin (2 u))

\int 2 sin^{6} (u) d u = 2 (- \frac{cos ( u ) sin ^{5} ( u )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (u) cos (u) + \frac{3}{8} (u - \frac{1}{2} sin (2 u))))

\int sin^{8} (u) d u = - \frac{cos ( u ) sin ^{7} ( u )}{8} + \frac{7}{8} (- \frac{cos ( u ) sin ^{5} ( u )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (u) cos (u) + \frac{3}{8} (u - \frac{1}{2} sin (2 u))))

= 2 (- \frac{1}{4} sin^{3} (u) cos (u) + \frac{3}{8} (u - \frac{1}{2} sin (2 u)) - 2 (- \frac{cos ( u ) sin ^{5} ( u )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (u) cos (u) + \frac{3}{8} (u - \frac{1}{2} sin (2 u)))) - \frac{cos ( u ) sin ^{7} ( u )}{8} + \frac{7}{8} (- \frac{cos ( u ) sin ^{5} ( u )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (u) cos (u) + \frac{3}{8} (u - \frac{1}{2} sin (2 u)))))

代用を戻す

u = \frac{x}{2}

= 2 (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{8} (\frac{x}{2} - \frac{1}{2} sin (2 \cdot \frac{x}{2})) - 2 (- \frac{cos ( \frac{x}{2} ) sin ^{5} ( \frac{x}{2} )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{8} (\frac{x}{2} - \frac{1}{2} sin (2 \cdot \frac{x}{2})))) - \frac{cos ( \frac{x}{2} ) sin ^{7} ( \frac{x}{2} )}{8} + \frac{7}{8} (- \frac{cos ( \frac{x}{2} ) sin ^{5} ( \frac{x}{2} )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{8} (\frac{x}{2} - \frac{1}{2} sin (2 \cdot \frac{x}{2})))))

簡素化

2 (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{8} (\frac{x}{2} - \frac{1}{2} sin (2 \cdot \frac{x}{2})) - 2 (- \frac{cos ( \frac{x}{2} ) sin ^{5} ( \frac{x}{2} )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{8} (\frac{x}{2} - \frac{1}{2} sin (2 \cdot \frac{x}{2})))) - \frac{cos ( \frac{x}{2} ) sin ^{7} ( \frac{x}{2} )}{8} + \frac{7}{8} (- \frac{cos ( \frac{x}{2} ) sin ^{5} ( \frac{x}{2} )}{6} + \frac{5}{6} (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{8} (\frac{x}{2} - \frac{1}{2} sin (2 \cdot \frac{x}{2}))))) : 2 (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{16} (x - sin (x)) - \frac{3}{256} (5 (3 (x - sin (x)) - 4 sin^{3} (\frac{x}{2}) cos (\frac{x}{2})) - 16 sin^{5} (\frac{x}{2}) cos (\frac{x}{2})) - \frac{1}{8} sin^{7} (\frac{x}{2}) cos (\frac{x}{2}))

= 2 (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{16} (x - sin (x)) - \frac{3}{256} (5 (3 (x - sin (x)) - 4 sin^{3} (\frac{x}{2}) cos (\frac{x}{2})) - 16 sin^{5} (\frac{x}{2}) cos (\frac{x}{2})) - \frac{1}{8} sin^{7} (\frac{x}{2}) cos (\frac{x}{2}))

定数を解答に追加する

= 2 (- \frac{1}{4} sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) + \frac{3}{16} (x - sin (x)) - \frac{3}{256} (5 (3 (x - sin (x)) - 4 sin^{3} (\frac{x}{2}) cos (\frac{x}{2})) - 16 sin^{5} (\frac{x}{2}) cos (\frac{x}{2})) - \frac{1}{8} sin^{7} (\frac{x}{2}) cos (\frac{x}{2})) + C

グラフ

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