maclaurin e^{3x}cos(2x)

Lösung

maclaurin

e^{3 x} cos (2 x)

1 + 3 x + \frac{5}{2} x^{2} - \frac{3}{2} x^{3} - \frac{119}{24} x^{4} + \dots

Schritte zur Lösung

Apply the Maclaurin Formula

= 1 + \frac{\frac{d}{d x} ( e ^{3 x} cos ( 2 x ) ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( e ^{3 x} cos ( 2 x ) ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( e ^{3 x} cos ( 2 x ) ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= 1 + \frac{3}{1 !} x + \frac{5}{2 !} x^{2} + \frac{- 9}{3 !} x^{3} + \frac{- 119}{4 !} x^{4} + \dots

Fasse zusammen

= 1 + 3 x + \frac{5}{2} x^{2} - \frac{3}{2} x^{3} - \frac{119}{24} x^{4} + \dots

\frac{d}{d x} ((5 x^{2} - 7 x) e^{x})

in v erse l a pl a ce \frac{0.5}{s ^{2}}

\int \frac{tan ^{3} ( \frac{9}{z} )}{z ^{2}}

\frac{d}{d x} ((lo g_{2} (x))^{2})

x \to 1 - lim (\frac{- 3 x - 1}{x - 1})