y^'=e^{(3x+2y)}

解答

y^{^{'}} = e^{(3 x + 2 y)}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

求解步骤

y^{'} (x) = e^{(3 x + 2 y)}

求解可分离方程:

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

y = - \frac{ln ( - \frac{2}{3} e ^{3 x} - c _{1} )}{2}

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