xy^2y^'=y^3-1x^3

Lösung

x y^{2} y^{^{'}} = y^{3} - 1 x^{3}

y = x 3 - 3 ln (x) + c_{1}

Schritte zur Lösung

x y^{2} y^{'} (x) = y^{3} - 1 x^{3}

Solve Bernoulli ODE:

y = x 3 - 3 ln (x) + c_{1}

y = x 3 - 3 ln (x) + c_{1}

\frac{\partial}{\partial y} (\frac{- x}{( x + y ) ^{2}})

\int_{0}^{1} x 8 - x^{2} d x

(1 + ln (x) + \frac{y}{x}) d x = (7 - ln (x)) d y

x \to - 7 lim (\frac{1}{x + 7})

l a pl a ce t r an s f or m [t]