derivative f(x)=sqrt(x)+2

解答

导数

f (x) = x + 2

\frac{1}{2 x}

求解步骤

\frac{d}{d x} (x + 2)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (2)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (2) = 0

= \frac{1}{2 x} + 0

化简

= \frac{1}{2 x}

x \to - 1 lim (x^{2} - 3 x + 1)

\frac{d}{d x} (\frac{3 x - 1}{( 2 - x ) ^{2}})

d x - 2 x y d y = 0

\frac{d}{d x} (\frac{( x - 1 ) ( x ^{2} + x + 1 )}{x ^{3}})

t an g e n t f (x) = 3 - 2 x + 4 x^{3}, at x = - 1