integral of 1/(x^2)-\sqrt[3]{x}

Lösung

\int \frac{1}{x ^{2}} - 3 x d x

- \frac{1}{x} - \frac{3}{4} x^{\frac{4}{3}} + C

Schritte zur Lösung

\int \frac{1}{x ^{2}} - 3 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{x ^{2}} d x - \int 3 x d x

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

\int 3 x d x = \frac{3}{4} x^{\frac{4}{3}}

= - \frac{1}{x} - \frac{3}{4} x^{\frac{4}{3}}

Füge eine Konstante zur Lösung hinzu

= - \frac{1}{x} - \frac{3}{4} x^{\frac{4}{3}} + C

x \to - \infty lim (xx)

x \frac{d y}{d x} - (1 + x) y = y^{2}

in v erse l a pl a ce \frac{s + 7}{( s + 2 ) ( s - 5 )}

d er i v a t i v e y = \frac{e ^{x}}{ln ( x )}

d er i v a t i v e f (x) = (8 x^{3} + 2 x^{2})^{4}