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tangent 4/(x^2)

解答

切线

\frac{4}{x ^{2}}

解答

y = - \frac{8}{a _{0}^{3}} x + \frac{12}{a _{0}^{2}}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, \frac{4}{a _{0}^{2}})

计算

y = \frac{4}{x ^{2}}

的斜率:

\frac{d y}{d x} = - \frac{8}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{8}{a _{0}^{3}}

找到斜率 m=

- \frac{8}{a _{0}^{3}}

且穿过

(a_{0}, \frac{4}{a _{0}^{2}})

的直线:

y = - \frac{8}{a _{0}^{3}} x + \frac{12}{a _{0}^{2}}

y = - \frac{8}{a _{0}^{3}} x + \frac{12}{a _{0}^{2}}

作图

流行的例子

t an g e n t \frac{9}{x}

斜率 x^2+xy-(y^2)/4 =1

s l o p e x^{2} + x y - \frac{y ^{2}}{4} = 1

derivative f(x)=(5x+2x^2)^2

d er i v a t i v e f (x) = (5 x + 2 x^{2})^{2}

inverselaplace 4/(s+3)

in v erse l a pl a ce \frac{4}{s + 3}

integral of (4x^{19}-5x^{-8})/(x^2)

\int \frac{4 x ^{19} - 5 x ^{- 8}}{x ^{2}} d x