integral of (ln(4x))/(x^2)

解答

\int \frac{ln ( 4 x )}{x ^{2}} d x

- \frac{ln ( 4 x )}{x} - \frac{1}{x} + C

求解步骤

\int \frac{ln ( 4 x )}{x ^{2}} d x

使用分布积分法

= - \frac{ln ( 4 x )}{x} - \int - \frac{1}{x ^{2}} d x

\int - \frac{1}{x ^{2}} d x = \frac{1}{x}

= - \frac{ln ( 4 x )}{x} - \frac{1}{x}

解答补常数

= - \frac{ln ( 4 x )}{x} - \frac{1}{x} + C

\frac{\partial}{\partial y} (y ln (y) - e^{- x y})

\int \frac{3 x + 1}{x ^{2} - 10 x + 28} d x

d er i v a t i v e 200 (e)^{0.03 x}

a re a y = x^{4} - 3 x^{2} + 3, y = x^{2}

\frac{d}{d v} (\frac{3 v - 2 v e ^{v}}{v})