What is the derivative of f(x)=4x^{-1/8} ?

The derivative of f(x)=4x^{-1/8} is -1/(2x^{9/8)}

What is the first derivative of f(x)=4x^{-1/8} ?

The first derivative of f(x)=4x^{-1/8} is -1/(2x^{9/8)}

derivative of

f (x) = 4 x^{- \frac{1}{8}}

- \frac{1}{2 x ^{\frac{9}{8}}}

Solution steps

\frac{d}{d x} (4 x^{- \frac{1}{8}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (x^{- \frac{1}{8}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 4 (- \frac{1}{8} x^{- \frac{1}{8} - 1})

Simplify

4 (- \frac{1}{8} x^{- \frac{1}{8} - 1}) : - \frac{1}{2 x ^{\frac{9}{8}}}

= - \frac{1}{2 x ^{\frac{9}{8}}}

\int x ln (3 x) d x

t an g e n t f (x) = - \frac{1}{x}

d er i v a t i v e f (x) = 1 + x

\int \frac{\frac{π}{6}}{0} sin (x) cos^{3} (x) d x

in v erse l a pl a ce \frac{1}{s ^{2}}

What is the derivative of f(x)=4x^{-1/8} ?
The derivative of f(x)=4x^{-1/8} is -1/(2x^{9/8)}
What is the first derivative of f(x)=4x^{-1/8} ?
The first derivative of f(x)=4x^{-1/8} is -1/(2x^{9/8)}