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人気のある微分積分 >

x^{''}+2x=0,x(0)=1,x(1)=0

解

x^{^{''}} + 2 x = 0, x (0) = 1, x (1) = 0

解

x = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

解答ステップ

x^{''} (t) + 2 x = 0

線形 ODE を解く:

x = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

x = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

人気の例

勾配 y=x^2-2x-2P(y,x),(2,-2)

s l o p e y = x^{2} - 2 x - 2 P (y, x), (2, - 2)

limit as x approaches 0 of x/(sin(2x))

x \to 0 lim (\frac{x}{sin ( 2 x )})

面積 (2)sin(x),[0,pi]

a re a (2) sin (x), [0, π]

integral of ((x^2-x+12))/((x^3+3x))

\int \frac{( x ^{2} - x + 12 )}{( x ^{3} + 3 x )} d x

integral of 2-y

\int 2 - y d y