x^{''}+2x=0,x(0)=1,x(1)=0

Lösung

x^{^{''}} + 2 x = 0, x (0) = 1, x (1) = 0

x = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

Schritte zur Lösung

x^{''} (t) + 2 x = 0

Solve linear ODE:

x = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

x = cos (2 t) - \frac{cos ( 2 ) sin ( 2 t )}{sin ( 2 )}

s l o p e y = x^{2} - 2 x - 2 P (y, x), (2, - 2)

x \to 0 lim (\frac{x}{sin ( 2 x )})

a re a (2) sin (x), [0, π]

\int \frac{( x ^{2} - x + 12 )}{( x ^{3} + 3 x )} d x

\int 2 - y d y