integral of 7sqrt(16-2x)-14

Lösung

\int 7 16 - 2 x - 14 d x

- \frac{7}{3} (16 - 2 x)^{\frac{3}{2}} - 14 x + C

Schritte zur Lösung

\int 7 16 - 2 x - 14 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 7 16 - 2 x d x - \int 14 d x

\int 7 16 - 2 x d x = - \frac{7}{3} (16 - 2 x)^{\frac{3}{2}}

\int 14 d x = 14 x

= - \frac{7}{3} (16 - 2 x)^{\frac{3}{2}} - 14 x

Füge eine Konstante zur Lösung hinzu

= - \frac{7}{3} (16 - 2 x)^{\frac{3}{2}} - 14 x + C

x \to - 7 - lim (\frac{x + 6}{x + 7})

n = 1 \sum \infty (\frac{x}{2})^{n}

\int (x + 3) (x - 7) d x

a re a x^{2} - 3, 5 - x^{2}

\frac{\partial}{\partial x} (x^{2} + 2 y^{2} + x y^{2} + 1)