What is the integral from 1 to 9 of (sqrt(x)) ?

The integral from 1 to 9 of (sqrt(x)) is 52/3

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integral from 1 to 9 of (sqrt(x))

\int_{1}^{9} (x) d x

\frac{52}{3}

Decimal Notation

17.33333 \dots

Solution steps

\int_{1}^{9} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{9}

= [\frac{2}{3} x^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

\frac{52}{3}

= \frac{52}{3}

\int 49 d x

\frac{\partial}{\partial x} (4 y^{2} x^{3} - 3 y x^{2})

x^{^{''}} + 4 x^{^{'}} + 2 x = 0

\int (5 e^{- 0.8 x}) d x

y = 2 x e^{2 x} - e^{2 x}

What is the integral from 1 to 9 of (sqrt(x)) ?
The integral from 1 to 9 of (sqrt(x)) is 52/3