What is the derivative of t^3-t ?

The derivative of t^3-t is 3t^2-1

What is the first derivative of t^3-t ?

The first derivative of t^3-t is 3t^2-1

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derivative of

t^{3} - t

3 t^{2} - 1

Solution steps

\frac{d}{d t} (t^{3} - t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (t^{3}) - \frac{d t}{d t}

\frac{d}{d t} (t^{3}) = 3 t^{2}

\frac{d t}{d t} = 1

= 3 t^{2} - 1

\frac{d}{d x} (1 - x^{2} - x arccos (x))

y \frac{d y}{d x} = - 8 cos (π x)

\frac{\partial}{\partial x} (csc^{2} (x))

n = 0 \sum \infty n \cdot e^{- n^{2}}

y = 4 ln (x)