sum from n=0 to infinity of (0.02)^n

Lösung

n = 0 \sum \infty (0.02)^{n}

1.02040 \dots

Schritte zur Lösung

n = 0 \sum \infty 0.0 2^{n}

Geometrischen Test der Reihe anwenden:

1.02040 \dots

= 1.02040 \dots

\int 5 e^{x} d x

x \to 4 lim (x - 4)

\int_{1}^{16} \frac{x - 3}{x} d x

y^{^{'}} = 1 + 4 y^{2}

t an g e n t f (x) = \frac{6 x}{x + 5}, at x = - 3