xy^'=y+5x^2sin(x)

Lösung

x y^{^{'}} = y + 5 x^{2} sin (x)

y = - 5 cos (x) x + c_{1} x

Schritte zur Lösung

x y^{'} (x) = y + 5 x^{2} sin (x)

Solve linear ODE:

y = - 5 cos (x) x + c_{1} x

y = - 5 cos (x) x + c_{1} x

d er i v a t i v e f (x) = (2 x^{3} + 6 x) (4 x^{2} - 7 x + 11)

\frac{d}{d x} (\frac{x ^{2}}{x ^{2} - 4})

\frac{\partial}{\partial y} (\frac{x + y}{x y - 1})

\int \frac{x ^{2} + 3}{x} d x

t an g e n t 2 x (5 - 4 x)^{4}, at x = 1