derivative of x^3-2x^2+x-20

解

\frac{d}{d x} (x^{3} - 2 x^{2} + x - 20)

3 x^{2} - 4 x + 1

解答ステップ

\frac{d}{d x} (x^{3} - 2 x^{2} + x - 20)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2 x^{2}) + \frac{d x}{d x} - \frac{d}{d x} (20)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d x}{d x} = 1

\frac{d}{d x} (20) = 0

= 3 x^{2} - 4 x + 1 - 0

簡素化

= 3 x^{2} - 4 x + 1