(x^3-25x^2)^'

Lösung

(x^{3} - 25 x^{2})^{^{'}}

3 x^{2} - 50 x

Schritte zur Lösung

(x^{3} - 25 x^{2})^{'}

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= (x^{3})^{^{'}} - (25 x^{2})^{^{'}}

(x^{3})^{'} = 3 x^{2}

(25 x^{2})^{'} = 50 x

= 3 x^{2} - 50 x

\int arctan (\frac{2 x}{1 - x ^{2}}) d x

\frac{\partial}{\partial x} (1 + 3 x + 2 y^{2})

\frac{\partial}{\partial y} (\frac{y}{7 x})

\int_{1}^{4} (x) d x

\frac{d y}{d x} - \frac{y}{x} = 6 x e^{x}